HI there,

Re the last point - could you give a specific example? It seems that it is already the case that

a |> x.y

is interpreted with precedence that makes it equivalent to this:

a |> (x.y)

thx

By on 12/29/2010 1:02 AM ()

Finally found an example where the . operator's precedence is odd.

ignore (Async.AwaitTask(!bufferMergerTask))

works, but
ignore Async.AwaitTask(!bufferMergerTask)

doesn't.

By on 1/12/2011 2:46 AM ()

I don't think the precedence of dot is at fault here. The problem is that the second alternative is the same as

1
ignore Async.AwaitTask (!buggerMergerTask)
By on 1/12/2011 11:43 AM ()
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