You can apply Seq.max:

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let m = matrix [[1.0; 2.0; 3.0];
                [4.0; 5.0; 6.0];
                [7.0; 8.0; 9.0]]


Seq.max (m.Row(2));;

:-)

By on 6/3/2010 6:39 AM ()

Haha cooooooooooooooool

Thanks!

By on 6/4/2010 6:15 AM ()
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