I've got the array created, it's getting a single dimension (which basically means a 1D array) out of it. If you make a 2D array like this:

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let arr = Array2.create 10 10 0;;

you get, predictably, an 2D array containing ten 1D arrays, all initialized to 0. But if you then try to get the first dimension (the first 1D array) like this:

arr.(0);;

which is how you'd do it in C# (specifying only the first index gives you the full array at that index), I get an error saying "This expression has type int [,] but is here used with type 'a array". Am I missing a cast?

DC

This because Array2.create a regular array, with all deminisions the same size. It only allows access to the individual members. If you look at the type of the object this gives a strong hint on how to access the members, to acess them you use a two deminsional look up .(0,0).

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let regular = Array2.create 2 2 1
let i = regular.(0,0)

AFAIK you can't get a single dimention like that. Array2 is probably there as a conveniance (so you don't have to simulate a contiguous square array with a flat array + indexing function). As Robert pointed out, the alternative is an array of arrays (aka jagged array). Something like:

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let arr = Array.create 10 (Array.create 10 0)

arr.(0)

Regards.

--

Ben Jackson.