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Interface declaration question (easy)
f#

Hi,

I'm not quite understand how to declare interface one member of which takes more than one parameters:

type IFoo=
//method Boo takes x y z parameters and returns nothing
abstract Boo: int->int ->int->unit

let test_foo (foo:IFoo) =
foo.Boo(10,10,10)

In this example I have got an the following problem:
error: The member or object constructor 'Boo' takes 1 argument(s) but is here supplied with 3. The signature of the member is abstract member IFoo.Boo: int -> (int -> int -> unit).

Thanks,
Sorry if the question is stupid ;)

Regards,
-Artjom

.

Hi,

Here are different possibilities.

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type IFoo =
    abstract Boo: (int * int * int) -> unit

type Foo() =
    interface IFoo with
       member x.Boo tuple = 
          ()

let test_foo (foo:IFoo) = 
    foo.Boo((10, 10, 10))

 

type IFoo2 =
    abstract Boo: int -> int -> int -> unit

type Foo() =
    interface IFoo2 with
       member x.Boo x y z = 
          ()

let test_foo (foo:IFoo2) =
    foo.Boo 10 10 10

 


type IFoo3 =
    //method Boo takes x y z parameters and returns nothing
    abstract Boo: int * int * int -> unit

type Foo() =
    interface IFoo3 with
       member x.Boo(x, y, z) = 
          ()

let test_foo (foo:IFoo3) = 
    foo.Boo(10, 10, 10)

Laurent.

By on 4/23/2008 9:10 AM ()

Hi LLB,

Thanks for quick answer. It works! So easy!

It looks like I still confusing of so rich syntax (many contructions which the language supports) and still don't "feeling" them. Need more practice :)

By on 4/23/2008 9:32 AM ()

Another example:

type IFoo=
//method Boo takes a tuple x*y*z parameters and returns nothing
abstract Boo: int*int*int->unit

type Foo() =
interface IFoo with
x.Boo x,y,z =
()

error: only simple variable patterns can be bound in 'let rec' constructs.

By on 4/23/2008 8:41 AM ()

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