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decodeFloat
f#

Hi,

In Haskell there is a function called decondeFloat, which takes a floating point number and turns it into a tuple (a,b), where a is an integer containing the part before the comma, and b is an integer containing the part after the comma.

e.g. decodeFLoat 67.3425 = (67, 3425)

Is there an equivalent in F#, and if not, how can I write one? I know about Math.Truncate, but the part after the comma eludes me...

cheers,

Kurt

.

Hi, Kurt.

As far as I can judge, You are mistaken. The Haskell function decodeFloat applied to a real floating-point number returns the significand expressed as an Integer and an appropriately scaled exponent (an Int). I.e. if decodeFloat x return (m,n), then x = m*2^n.

For example, decodeFloat 67.3425 gives (4738807154784338,-46).

By on 4/27/2008 10:20 AM ()

(red face) you're right...thanks for the heads up!

By on 4/28/2008 1:50 AM ()

What about something like:
let decodeFloat x =
let fx = floor x
fx, x - fx

By on 4/25/2008 10:51 AM ()

Your decodeFlaot 12.45 = (12, 0.45). I want (12, 45)

I guess I should write x to string, split it and parse both parts again as int. I just hoped I overlooked some obvious solution.

Kurt

By on 4/25/2008 12:59 PM ()

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