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How to declare a mutually dependent type and function?
f#

For example,

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let foo = Console.WriteLine("foo")

and Bar<'a> = Bar of int with member x.bar = foo

That doesn't work, neither does adding let rec, neither does reversing the order, i.e.

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type Bar<'a> = Bar of int with member x.bar = foo

and foo = Console.WriteLine("foo")

any ideas?

cheers,

Kurt

.

How about making the function a static member of the type? If necessary, you can still define an external function that forwards all calls to the static function.

Stephan

By on 9/23/2008 1:12 PM ()

Yes; unfortunately there is not yet any way in the language to do this directly. Here's the explicit version of the suggested workaround:

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#light

type Bar = 
    Bar of int 
        member x.bar = Bar.foo()
        static member foo() = System.Console.WriteLine("foo") 
let foo() = Bar.foo()
By on 9/23/2008 2:19 PM ()

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